Bicycle Bike Cyclist
physics problem with a bike need help asap?
A cyclist begins pedaling a bicycle from a complete stop to a constant speed.
Accelerating at a constant rate, after 10.0 minutes, the cyclist is pedaling at 60.0 (pedal)
revolutions per minute and cruises at this rate for the duration of the trip. The bike is geared with a
2:1 ratio, meaning that the rear wheel of the bike turns one revolution for every two revolutions of
the pedals. How far does the bike rider travel during a 30.0 minute duration?
is the circumference of the wheel given? You can substitute circumference of the tire (distance) for revolutions. 1 revolution =x distance (circumference)
first 10 min: use x= vt+1/2 a t^2 (first 10 mintues; v=0) you need to calculate acceleration for the 10 minutes (rev/min^2)
next 20 min (60rev ped/min *20 min * 1rev wheel/2rev ped) units will cancel to give you: 600 rev wheel
600 rev wheel * circ of wheel/1 rev of wheel
Add first 10 min distance and next 20 min distance
I hope this helps. tell me if im wrong
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